F(x)=x^3-1/x^3 find f(x) f(1/x) 276996

Area between y = x^2 and x = 1 and x = 3F (x) = (x1) (x2) (x3) , x ∈ 0,4, ∴ f (x) = x 3 6x 2 11x 6 As f (x) is a polynomial in x (1) f (x) is continuous on 0, 4 (2) f (x) is differentiable on (0, 4) Thus, all the conditions of LMVT are satisfied To verify LMVT we have to find c ∈ (0,4) such thatThe output f (x) is sometimes given an additional name y by y = f (x) The example that comes to mind is the square root function on your calculator The name of the function is \sqrt {\;\;} and we usually write the function as f (x) = \sqrt {x} On my calculator I input x for example by pressing 2 then 5 Then I invoke the function by pressing

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F(x)=x^3-1/x^3 find f(x) f(1/x)- If f(x)=3x2,find f^1(x) Get the answers you need, now!Calculus Examples Popular Problems Calculus Find the Critical Points f (x)=x^ (1/3) (x4)

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Answer to 1 Find f '(x) and f ''(x) f(x) = (x3 5)ex 2 3Mr Dwyer is available for 1on1 tutoring online Details at https//www4tutorcom/onlinetutoringRestated that is f(x)=2x^21 and g(x)=x4 find (fog) (x) Solve the following x log base 2(3x5)=3log2 (3x5)=3 Answer by longjonsilver(2297) ( Show Source )

Related Queries calculate how drenched I would become if I walked in the rain; 36 A function g is described below g(x) = (x 3)2 1 • The domain of g is all real numbers greater than 0 The range of g is all real numbers gre ater than or equal to F 1 H 3 G 3Osculating circle y = 1/x^2 at x = 2;

Find {eq}\displaystyle f'' (1) {/eq}, if {eq}\displaystyle f(x) = 3 x^2 5 x 7 {/eq} Second Derivative The second derivative of the function is the derivative of the first derivative or justSimple and best practice solution for f(x)=(x3)(3x1)(x1) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve itAlgebra Examples Popular Problems Algebra Find the Inverse Function f (x)=x^31

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Find f'(a) f(x) = x^{2} Video Transcript So for this problem, we're going to be taking the derivative of ffx and then we want to evaluate it at a specific value at this point for this problem is just gonna be the value of a So what we have is ffx is equal to X to the negative, tooGiven f(x) = x^3 3x^2 – 1 Use the first or second derivative tests to a) Find the relative extrema b) Determine the intervals where the graph is increasing or decreasingShort Solution Steps f ( x ) = x ^ { 3 } ( 1 \frac { 4 } { x 6 } ) f ( x) = x 3 ( 1 − x 6 4 ) To add or subtract expressions, expand them to make their denominators the same Multiply 1 times \frac {x6} {x6} To add or subtract expressions, expand them to make their denominators the same

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3 (x 1)2 − 7 View solution steps Solution Steps f ( x ) = 3 ( x 1 ) ^ { 2 } 7 f ( x) = 3 ( x 1) 2 − 7 Use binomial theorem \left (ab\right)^ {2}=a^ {2}2abb^ {2} to expand \left (x1\right)^ {2} Use binomial theorem ( a b) 2 = a 2 2 a b b 2 to expand ( x 1) 2 3\left (x^ {2}2x1\right)7Explanation Using the defined function, f(a) will produce the same result when substituted for x f(a) = a 2 – 5 Setting this equal to 4, you can solve for a a 2 – 5 = 4 a 2 = 9 a = –3 or 3Y=f(x)= x 3 による逆像。 立方根 3 √の定義 ※一般化：べき関数y=x n によ る逆像

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Answer to If f(x) = 3x 7 and g(x) = (x)^{3} 1, then find (f \\circ g)(2) By signing up, you'll get thousands of stepbystep solutions to f(x) = {(3x)/(1x)} 23x taking log on both sides log(fx) = (2 3x) log {(3x)/(1x)} log(fx) = (2 3x) log(3x) log(1x) Now differentiate f'(x) /f(x) = (21 The continuos function f R → R defined by rule f(x) = x5 x3 x is stricly incrasing, then the equation f(x) = 3 has only a single solution But 15 13 1 = 3, then x = 1 is single solution the equation f(x) = 3 therefore f − 1(3) = 1 Clearly f − 1(f(2)) = 2 because f is bijection Share

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Understanding function notationNeed more help?ML Aggarwal Solutions for Class 10 Maths Chapter 6 Factorization p = 6/6 p = 1 Therefore, value of p is 1 (ii) Find 'a' if the two polynomials ax3 3x2 – 9 and 2x3 4x a, leaves the same remainder when divided by x 3Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history

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X!a f(x) g(x) = 1, If the values of f(x) g(x) are negative as x!ain the above situation, then lim x!a f(x) g(x) = 1 , If on the other hand, if lim x!ag(x) = 0 = lim x!af(x), we cannot make any conclusions about the limit Example Find lim x!ˇ cosx x ˇ As xapproaches ˇfrom the left, cosxapproaches a nite number 1 As xapproaches ˇfrom theFor example, if f is a function that has the real numbers as domain and codomain, then a function mapping the value x to the value g(x) = 1 / f(x) is a function g from the reals to the reals, whose domain is the set of the reals x, such that f(x) ≠ 0 The range of a function is the set of the images of all elements in the domainCorrect answer \displaystyle 35 Explanation To get each member of this sequence, add a number that increases by one with each element \displaystyle 7 1 = 8 \displaystyle = 10 \displaystyle 103= 13 \displaystyle 134=17

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F (x) = (x3)/ (x1) Let f (x) = u/v such that\ u= x3 ==> u' = 1 v= x1 ==> v'= 1 f' (x) = (u'v uv')/v^2 = 1* (x1) (x3)*1/ (x1)^2 = (x1 x 3)/ (x1)^2 = 4/ (x1)^2 f' (0) = 4F(x3) = 5x2 f(x3) = 5(x3)13 That is f(x) = 5x13 or f(x3) = 5x2 put x = x3 f(x33) =5(x3)2 f(x) = 5x152 f(x) = 5x13Answer to If f(x) x2f(x)3 = 10 and f(1) = 2, find f '(1)f '(1) =

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 1 Answer Monzur R In order to find for any function f (x), we must apply the 'transformation' y = x In order to do that, we must define x in terms of y, ie, find f (y), then set y = x Let y = f (x) y = (x − 3)3 1 y − 1 = (x −3)3 x − 3 = 3√y − 1Solution for f (x)=x^31 equation Simplifying f (x) = x 3 1 Multiply f * x fx = x 3 1 Reorder the terms fx = 1 x 3 Solving fx = 1 x 3 Solving for variable 'f' Move all terms containing f to the left, all other terms to the right Divide each side by 'x' f = 1x 1 x 2 Simplifying f = 1x 1 x 2G(x) = tanh(2x) gives f(x) = (1 x4) 128x4 Not a polynomial, but at least a rational function g(x) = tanh(3 2x) gives f(x) = 1 x3 which is the answer given by juantheron For RHS to be a polynomial you have a0 = 1 or a0 ≠ 1 and ai = 0 for i > 0 (which contradicts an ≠ 0 )

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Q Evaluate lim f(x) and lim f(x) for the following function Then give the horizontal asymptote of f ( Then give the horizontal asymptote of f ( A Click to see the answerMathf(x1)=2x3/math Let matht=x1\implies x=t1/math math\therefore f(t)=2(t1)3/math mathf(t)=2t5/math matht/math can be replaced by mathx1 Example 1 f(x) = x We'll find the derivative of the function f(x) = x1 To do this we will use the formula f (x) = lim f(x 0 0) Δx→0 Δx Graphically, we will be finding the slope of the tangent line at at an arbitrary point (x 0, 1 x 1 0) on the graph of y = x (The graph of y = x 1 is a hyperbola in the same way that the graph of

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Let f be a real valued function defined on the interval (− 1, 1) such that e − x f ( x ) = 2 ∫ x t 2 1 d t , ∀ x ∈ ( − 1 , 1 ) and let f − 1 be the inverse function of fIf f (x) = x1/x1 then find the value of f (2x) Find the answer to this question along with unlimited Maths questions and prepare better for JEE examination> 1 Taylor polynomials > 11 The Taylor polynomial Example Find a quadratic polynomial p 2(x) to approximate f(x) near x= a Since p 2(x) = b 0 b 1xb 2x2 we impose three conditions on p 2(x) to determine the coefficientsTo better mimic f(x) at x= awe require

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 Ex 13, 3Find 𝑔𝑜𝑓 and 𝑓𝑜𝑔, if(i) f(x) = 𝑥 and g (x) = 5𝑥 −2f(x) = 𝑥 , g(x) = 5𝑥−2f(x) = 𝑥f(g(x)) = 𝑔(𝑥)fog(x) = (5𝑥 −2) = 𝟓𝒙 −𝟐g(x) = 5𝑥 −2g(f(x)) =5𝑓(𝑥) −2gof (x) = (𝟓𝒙−𝟐) Misc 7 Find intervals f(x) = x3 1/x3 x = 0 is increasing Misc 7 Find the intervals in which the function f given by f (x) = x3 1/𝑥^3 , 𝑥 ≠ 0 is (i) increasing (ii) decreasingf(𝑥) = 𝑥3 1/𝑥3Finding f'(𝒙) f'(𝑥) = 𝑑/𝑑𝑥 (𝑥^3𝑥^(−3) )^ = 3𝑥2 (−3)^(−3 − 1)= 3𝑥2 – 3𝑥^(−4)= 3𝑥^2−3/𝑥^4 = 3(𝑥^2−1/𝑥^4Use Descartes' Rule of Signs to find the number of real roots off (x) = x5 4x4 – 3x2 x – 6 First, I look at the positiveroot case, which is looking at f (x) f ( x) = x5 4 x4 – 3 x2 x – 6 The signs flip three times, so there are three positive roots, or one positive root Either way, I definitely have at least one positive

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1 f X(y 1 n) where, f X() is the pdf of X which is given Here are some more examples Example 1 Suppose Xfollows the exponential distribution with = 1 If Y = p X nd the pdf of Y Example 2 Let X ˘N(0;1) If Y = eX nd the pdf of Y Note Y it is said to have a lognormal distribution Example 3 Let Xbe a continuous random variable with pdf fInverse\f (x)=\frac {1} {x^2} inverse\y=\frac {x} {x^26x8} inverse\f (x)=\sqrt {x3} inverse\f (x)=\cos (2x5) inverse\f (x)=\sin (3x) functioninversecalculator enThen I'll make it simpler for us in the long run, that tells us that F prime of X is going to be X to the negative one over a negative one, which is just negative one over Acts plus C That tells us that F of X is going to be equal to negative the anti derivative of one over X is actually going to be the natural log of the absolute value of X

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Find (f B g)(3) and (g B f)(3) if f ( x ) = x 2 and g ( x ) = 4 – x2 Solution Step 1 Find (f B g)(x) then evaluate for 3 Since (f B g)(x) = f( g(x) ), then = f(4 – x2) = (4 – x 2) 2 = 6 – x 2 Evaluating for 3 (f B g)(3) = 6 – (3)2 = 6 – 9 = 3 0DWK 6WXGHQW /HDUQLQJ $VVLVWDQFH &HQWHU 6DQ $QWRQLR &ROOHJHF (x)= 1−x3 −x5The critical point of F (x) are the values of xfor which either f ′(x) does not exist or f ′(x)= 0So f (x)= 1−x3 −x5f ′(x) = −3x2 −5x4f ′(x) = 0 when x = 0x = 0 is the only critical point because 35x2 > 0for all x ∈ Rf is decreasing on all the x value (x ∈ R)because f ′(x) < 0 for all xOne class collects 8 1/4 pounds of recyclable materials Another class collects 1 1/2 times as many pounds as the first class

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